Math, asked by wwwalison8888a, 1 year ago

Longest rod which can be kept inside a rectangular box is 17cm.Length=12cm,breadth=8cm.Find the inner height...


wwwalison8888a: The height of the box.
ArchitectSethRollins: 12 cm
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Answers

Answered by Neershreyansh
19
so the length of the longest rod
which can kept in the room is
= 17.
hence height of room =
root under 17^2 -(12^2 +8^2)
》root under (289-208)
》root under 81.
》9 cm.is the height of room.

That's all

wwwalison8888a: Actually..I want the inner height..
wwwalison8888a: See..the question is longest rod which can be kept inside a rectangular box is 17cm.......plz read the question properly.
Neershreyansh: this is inner hight of rod.if there is no thickness.
wwwalison8888a: I wan the height of the box.
wwwalison8888a: I'm sorry I think ur wrong...
ArchitectSethRollins: wrong answer bro
Neershreyansh: okk
Neershreyansh: i ll correct
Answered by ArchitectSethRollins
72
Hi friend
--------------
Your answer
-------------------

Longest rod that. can be kept inside a rectangular box = The diagonal of the box

Measure of the rod = 17 cm

Length of the rectangular box = 12 cm

Breadth of the rectangular box = 8 cm

Height of the rectangular box =?

digonal \: of \: a \: cuboid \:  =  \sqrt{(length) {}^{2} +(breadth) {}^{2}   + (height) {}^{2}  }
17 =  \sqrt{(12) {}^{2}  + (8) {}^{2}  + (height) {}^{2}  }  \\  \\ (17 ) {}^{2} =  \: (  \sqrt{144 + 64 + (height) {}^{2} } ) {}^{2} .....squaring \: both \: sides \\  \\ 289 = 208 + (height) {}^{2}  \\  \\ (height) {}^{2}  = 289 - 208 \\  \\ (height) {}^{2} = 81 \\  \\ height =  \sqrt{81}  \\  \\ height = 9 \: cm
THEREFORE,
---------------------

The height of the rectangular box is 9 cm.

HOPE IT HELPS

#ARCHITECTSETHROLLINS

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wwwalison8888a: Thanks a lot..
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