Question

integrate 3x² + 4x - 1 dx​

Answer 1

Step-by-step explanation:

$\frac{d}{dx} 3 {x}^{2} + \frac{d}{dx} 4x - \frac{d}{dx}1 \\ 3 \frac{d}{dx} {x}^{2} + 4 \frac{d}{dx} x - 0$

$(3 \times 2 {x}^{2 - 1} ) +( 4 \times 1)$

$6x + 4$

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