Integrate (4x + 2/x) with respect to x.
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The method of integration by substitution may be used to easily compute complex integrals. Let us examine an integral of the form
ab f(g(x)) g'(x) dx
Let us make the substitution u = g(x), hence du/dx = g'(x) and du = g'(x) dx
With the above substitution, the given integral is given by
ab f(g(x)) g'(x) dx = g(a)g(b) f(u) du
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We know that
∫√(a^2 - x^2)dx = 1\2[x√(a^2 - x^2)] + 1\2[a^2 sin(x/a)] +c
Putting the value in above, we get
∫√(4 - x^2)dx = 1/2 [x√(2^2-x^2)] +1/2 [2^2 ×sin−1(x/2)] + c
∫√(4 - x^2)dx = 1/2 [x√(4-x^2)] + 1/2 [4sin-1(x/2)] + c
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