Question

integrate by partial fraction method
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Answer 1

Answer:

Step-by-step explanation:

2X + 3 / X^2 - 9 = 2X/ 3 / ( x + 3) ( x - 3)

Now, let x = -3

A ( -6) + B ( 0 ) = -3 or A = 1/2

x = 3 A ( 0 ) + b ( 6 ) = 0  or B = 3/2

{ [( 1/2)]/ x + 3] + (3/2 )/ x -3 } dx

= 1/2 in ( x + 3 ) + 3/2   in ( x - 3) + c

HOPE IT HELPS.!