Math, asked by bhavishikha8955, 1 year ago

integrate: cosx/1+e^x. lower limit -pi/2 and upper limit pi/2

Answers

Answered by santy2
0

Answer:

Step-by-step explanation:

We will get the integrates of each of the components as follows :

∫cos x + ∫eˣ

∫cos x = sin x

∫eˣ = eˣ

= Sin x + eˣ

Applying the limits :

[Sin(π/2) + e^(π/2)] - [Sin(-π/2) + e^(-π/2)]

π/2 = 1.570796

Doing the substitution we have :

[Sin(1.571) + e^(1.571) ] - [Sin(-1.571) + e^(-1.570)]

4.8361 - 0.183163 = 4.652937

Hence the answer to this question is :

4.652937

Note : If it is addition or subtraction we get the integrals separately then sum them or subtract them.

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