Question

integrate definite Integral.....​

Answer 1

Step-by-step explanation:

see the attachment....

Answer 2

Answer:

Step-by-step explanation:

let x^2 =t

then 2x dx =dt

x dx =dt/2

therefore

4∫x√a^2-x^2/√a^+x^2

4∫dt/2 (√a^2-t/√a^2+t)

2∫√a^2-t dt/√a^2+t

let a^2=z

2∫√z-t dt/√z+t

2∫z-t dt/√z^2-t^2

2{z∫dt/√z^2-t^2 - ∫tdt/√z^2-t^2}

2{zsin^-  t/z +√z^2-t^2 }

2{a^2sin^-  x^2/a^2 + √a^4-x^4}