integrate (e^tan^-x)/1+x^2
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integration of e^tan^-1x/(1+x^2)
let
tan^-1x =z
now differentiate
dx/(1+x^2)=dz
dx =(1+x^2)dz
put dx =(1+x^2)dz
now will be
integration of e^z.dz
hence integration of this =e^z +c
hence e^tan^-1x + c is integrant of above
let
tan^-1x =z
now differentiate
dx/(1+x^2)=dz
dx =(1+x^2)dz
put dx =(1+x^2)dz
now will be
integration of e^z.dz
hence integration of this =e^z +c
hence e^tan^-1x + c is integrant of above
angadsk1:
thanks for the help buddy
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