Question

Integrate integral 4(x^2-3)^2 dx​

Answer 1

Step-by-step explanation:

f(x)=4(x^2-3)^2

∫f(x).dx = ∫4(x^2-3)^2 . dx

= 4∫(x^2-3)^2 .dx

= 4∫x^4+9-6x^2 .dx

= 4( x^5/5 -2x^3 +9x +C )

= 4/5 x^5 - 8x^3 +36x +4C

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