Question

Integrate logx /x 2
Thanks

Answer 1

Use integration by parts..

u = Log x  and v = -1/x    ie.   dv = -1/x²

$I= \int\limits^{}_{} {Log x*\frac{1}{x^2}} \, dx \\\\=-\frac{Log x}{x}+ \int\limits^{}_{} {\frac{1}{x}*\frac{1}{x}} \, dx \\\\=-\frac{1+Log\ x}{x}+C$