Math, asked by meetaulakh98, 9 months ago

integrate sin2x÷1+sinx×sinx dx is

Answers

Answered by ashutoshsingh5452

0

Answer:

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Step-by-step explanation:

sin2x/1+sinx. sinx

(sin integral 2x^1+1/1+1 ) / ( 1+ sin integral x^1+1/1+1. sin integral x^1+1/1+1)

(sin2x^2/2) / ( 1+sinx^2/2. sinx^2/2)

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