Question

integrate sin2x /a cos^2x+bsin^2x its an urgent
​

Answer 1

Answer:

Answer

∫

acos

2

x+bsin

2

x

sin2xdx

Let

t=acos

2

x+bsin

2

x⇒dt=(−2acosxsinx+2bsinxcosx)dx

⇒

b−a

dt

=2sinxcosxdx

⇒

b−a

dt

=sin2xdx

∫

acos

2

x+bsin

2

x

sin2xdx

=

b−a

1

∫

t

dt

=

b−a

1

log∣t∣+c

=

b−a

1

log

∣

∣

∣

acos

2

x+bsin

2

x

∣

∣

∣

+c where t=acos

2

x+bsin

2

x

Step-by-step explanation:

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