Math, asked by Sunil111111, 1 year ago

integrate Sinx to the power4

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Answered by astitvastitva
0
 \int\limits {sin^4x} \ dx
 \int\limits { \frac{(1-cos(2x))^2}{2^2} } \ dx
 \frac{1}{4}  \int\limits {1-2cos(2x)+cos^2(2x)} \ dx
 \frac{1}{4}[x- \frac{2sin(2x)}{2}+ \int\limits { \frac{1+cox(4x)}{2} } \ dx  ]
\frac{1}{4}[x- \frac{2sin(2x)}{2}+  \frac{1}{2}(x+ \frac{sin(4x)}{4} )  ]
 \frac{1}{4}x+  \frac{1}{4}sin(2x)+ \frac{1}{8}x+ \frac{1}{32}sin(4x) +C

Sunil111111: for substituting sin you also need cos whch is not here
astitvastitva: Is that okay now?
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