integrate sinx underoot 1+cos2x
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Answer:
sinx1+cos2x−−−−−−−−√dx=−cos2x22–√+C
Step-by-step explanation:
∫sinx1+cos2x−−−−−−−−√dx
∫sinx1+2cos2x−1−−−−−−−−−−−−√dx
2–√∫sinxcosxdx
2√2∫sin2xdx
−cos2x22√+C
∫sinx1+cos2x−−−−−−−−√dx=−cos2x22–√+C
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