Question

Integrate the function : $\int \sqrt{1+x^2}\, dx$ is equal to
(A)$\frac x2 \sqrt{1+x^2}+\frac 12 \log \bigg\arrowvert \bigg(x+ \sqrt {1+x^2}\bigg)\bigg\arrowvert + C$
(B)$\frac 23 (1+x^2)^{\frac 32} + C$
(C)$\frac 23 x(1+x^2)^{\frac 32} + C$
(D)$\frac x2 \sqrt{1+x^2}+\frac 12 x^2\log \bigg\arrowvert x+ \sqrt {1+x^2}\bigg\arrowvert + C$

Answer 1

Answer:

Step-by-step explanation: