Math, asked by raghavgoyal0025, 7 months ago

integrate x^2+sinx bata do​

Answers

Answered by udayagrawal49
1

Solution:

Let I = \int{(x^{2}+sinx)}\,dx

⇒ I = \int{x^{2}}\,dx+\int{sinx}\,dx

⇒ I = \frac{x^{2+1}}{2+1} - cosx + C

⇒ I = \frac{x^{3}}{3} - cosx + C

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