Integrated rate equation for zero order reaction
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In some reactions, the rate is apparently independent of the reactant concentration. The rates of these zero-order reactions do not vary with increasing nor decreasing reactants concentrations. This means that therate of the reaction is equal to the rateconstant, k, of thatreaction
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Hey !!
Consider the general reaction : A ---> Products
If it is a reaction of zero order, Rate = -d [A ] / dt = k [A]° = k
(OR) d[A] = -k dt
Integrating both sides, we get [ A ] = kt + I -------> (1)
where I is a constant of integration At t = 0 , [A] = [A]₀ ∴ [A]= I
Substituting these values of I in eqn. (1), we get [A] = -kt + [A]₀ -----> (2)
(OR) kt = [A]₀ - [A] (or) k = 1 / t {[A]₀ - [A]} -----> (3)
This is the expression for rate constant for reaction of zero order.
HOPE IT HELPS YOU !!
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