Physics, asked by festival48, 8 months ago

Integration (1/x^2)(sinpi/x)dx

Answers

Answered by HARISHAM
1

Answer:

Using Integration by parts,. ∫ x2sinπxdx. = (−1π)x2cosπx+(2π2)xsinπx+(2π 3)cosπx+C. Remember that Integration

Explanation:

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