Question

integration 1^x(3+logx)dx​

Answer 1

Answer:

∫  

x(3+logx)

1

​

dx

Put logx=t

then  

x

1

​

.dx=dt

Substitute these values , we get

∫  

3+t

dt

​

 

=ln(3+t)+C

Put value of t,

 =ln(3+logx)+C

Step-by-step explanation: