integration 3x^2(x^3-4)dx
Answers
Question :
To evaluate
Solution :
We have ,
We know that
Then,
More About the topic :
The process of differentiation and integration are reverse of each other.
•Properties of the indefinite integral
1) The indefinite integral of sum or difference of two function is equal to sum or difference of their integrals respectively.
2) A constant factor of integrant may be taken outside the integral sign, if k is constant ,then
Answer:
Question :
To evaluate
\sf\int3x^2(x^3-4)dx∫3x
2
(x
3
−4)dx
Solution :
We have ,
\sf\int3x^2(x^3-4)dx∫3x
2
(x
3
−4)dx
\sf\int\:(3x^5-12x^2)dx∫(3x
5
−12x
2
)dx
\sf\int3x^5dx-\int12x^2dx∫3x
5
dx−∫12x
2
dx
We know that
\sf\int\:x^n=\dfrac{x{}^{n+1}}{n+1}∫x
n
=
n+1
x
n+1
Then,
\sf\int3x^5dx-\int12x^2dx∫3x
5
dx−∫12x
2
dx
\sf=\dfrac{3x{}^{5+1}}{5+1}-\dfrac{12x{}^{2+1}}{2+1}+c=
5+1
3x
5+1
−
2+1
12x
2+1
+c
\sf=\dfrac{3x^6}{6}-\dfrac{12x^3}{3}+c=
6
3x
6
−
3
12x
3
+c
\sf=\dfrac{x^6}{2}-4x^3+c=
2
x
6
−4x
3
+c
\sf=\dfrac{x^6-8x^3}{2}+c=
2
x
6
−8x
3
+c
$$\rule{200}2$$
More About the topic :
The process of differentiation and integration are reverse of each other.
•Properties of the indefinite integral
1) The indefinite integral of sum or difference of two function is equal to sum or difference of their integrals respectively.
$$\sf\int[f_1(x)\pm\:f_2(x)]dx=\int\:f_1(x)dx\pm\int\:f_2(x)dx$$
2) A constant factor of integrant may be taken outside the integral sign, if k is constant ,then
$$\sf\int\:kf(x)dx=k\int\:f(x)dx$$
Step-by-step explanation: