Math, asked by adarsh2497, 1 year ago

integration cos2x-cos2a/cosx-cosa dx​

Answers

Answered by rahulgrover033
11

∫(cos 2x - cos 2a) / (cos x - cos a) dx

= ∫((2cos^2 x - 1) - (2cos^2 a - 1)) / (cos x - cos a) dx

= ∫(2 cos^2 x - 2 cos^2 a) / (cos x - cos a) dx

= ∫[2(cos x - cos a)(cos x + cos a)] / (cos x - cos a) dx

= ∫2(cos x + cos a) dx

= 2 sin x + x cos a + c.

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