Question

integration of 1 divided by cosh x+sinh x

Answer 1

Answer:

-coshx+sinhx + c

Step-by-step explanation:

this is the answer

Answer 2

$\int\limits \frac{1}{coshx+sinhx}dx$ on R

we know $coshx-sinhx=1$

$coshx+sinhx$ can be written

$-(coshx-sinhx)=-1$

let $-(coshx-sinhx)$ be $x$

Now $=\int\limits \frac{1}{coshx+sinhx}dx$

$=\int\limits \frac{1}{-1}dx$    $\therefore \int\limits1dx=x+c$

$=\int\limits-1dx \Rightarrow -\int\limits 1dx$

$=\int\limits 1dx$

$=-x+c$

Sub $x=-(coshx-sinhx)\Rightarrow -x=coshx-sinhx$

$=-(coshx-sinhx)+c$

$=-coshx-sinhx +c$

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