Question

integration of 1/x^2.dx​

Answer 1

Explanation: For this antiderivative, you would use the power rule for antiderivatives/integrals. This states that ∫xn=1n+1(xn+1) . Since 1x2=x−2 and n≠−1 in this case, you can apply this power rule.

Answer 2

Answer:

-1/x + c

Explanation:

∫1/x² dx

⇒ ∫x⁻² dx

⇒ x⁻²⁺¹/2+1 + c

⇒ x⁻¹/-1 + c

∴ -1/x + c is the integration of 1/x²

Formulae:

∫xⁿ dx = xⁿ⁺¹/n+1 + c

∫eˣ dx = eˣ + c

∫1/x dx = ln|x| + c

∫sinx dx = -cosx + c

∫cosx dx = sinx + c

∫sec²x dx = tanx + c

∫cosec²x dx = -cotx + c

∫secxtanx dx = secx + c

∫cosecxcotx dx = -cosecx + c