integration of 1/x(x-1)
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The answer is....
= [1/x(x-1)]
= 1/(x^2-x)
= 1/x^2 - 1/x
= integration ( 1/x^2 - 1/x )
= integration (x^-2 - 1/x)
= x^-1 - log(x)
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= [1/x(x-1)]
= 1/(x^2-x)
= 1/x^2 - 1/x
= integration ( 1/x^2 - 1/x )
= integration (x^-2 - 1/x)
= x^-1 - log(x)
mark as brainliest.
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