Question

integration of 1÷y^2​

Answer 1

Explanation

Lets, just convert that into a power form,

1/y2 = y^−2

∫ y^−2dy

Using the power rule, ∫x^ndx = (x^n+1)/(n+1) +C,

(y^−1/−1) +C

Remember, y^−1 = 1/y,

(1/y)/−1 +C

−1/y +C