Question

integration of (2x-3)/(3x-4) dx​

Answer 1

Step-by-step explanation:

2x+33x+4=(3x+4)−x−13x+4

=3x+43x+4−x+13x+4

=1−x+13x+4

=1−13(3x+33x+4)

=1−13(3x+4−13x+4)

=1−13(3x+43x+4)+13(13x+4)

=1−13+13(13x+4)

=23+13(13x+4)

∫2x+33x+4dx

=∫(23+13(13x+4))dx

=∫(23+19(13x+4)(3))dx

=23x+19ln(3x+4)+c

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