Math, asked by BrainlyHelper, 1 year ago

integration of [2x - 3cosx + e^x].dx

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Answered by Ravi1435
0
this is answer .........
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Answered by abhi178
7

given, \int{[2x - 3cox + e^x]}\,dx

I = ∫[2x - 3cox + eˣ ]dx

= ∫2x.dx - ∫3cosx.dx + ∫eˣ.dx

= 2∫x.dx - 3∫cosx.dx + ∫eˣ.dx

= 2. \frac{x^2}{2}  - 3sinx + eˣ + C

= x² - 3sinx + eˣ + C

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