integration of [x³ + 3x + 4]\√x. dx
Answers
Answered by
11
HELLO DEAR,
given function is![\bold{\int{\frac{x^3 + 3x + 4}{\sqrt{x}}\,dx}} \bold{\int{\frac{x^3 + 3x + 4}{\sqrt{x}}\,dx}}](https://tex.z-dn.net/?f=%5Cbold%7B%5Cint%7B%5Cfrac%7Bx%5E3+%2B+3x+%2B+4%7D%7B%5Csqrt%7Bx%7D%7D%5C%2Cdx%7D%7D)
![\bold{\int{x^{5/2} + 3x^{1/2} + 4x^{-1/2}}\,dx} \bold{\int{x^{5/2} + 3x^{1/2} + 4x^{-1/2}}\,dx}](https://tex.z-dn.net/?f=%5Cbold%7B%5Cint%7Bx%5E%7B5%2F2%7D+%2B+3x%5E%7B1%2F2%7D+%2B+4x%5E%7B-1%2F2%7D%7D%5C%2Cdx%7D)
![\bold{\int{x^{5/2}}\,dx + 3\int{x^{1/2}}\,dx + 4\int{x^{-1/2}}\,dx} \bold{\int{x^{5/2}}\,dx + 3\int{x^{1/2}}\,dx + 4\int{x^{-1/2}}\,dx}](https://tex.z-dn.net/?f=%5Cbold%7B%5Cint%7Bx%5E%7B5%2F2%7D%7D%5C%2Cdx+%2B+3%5Cint%7Bx%5E%7B1%2F2%7D%7D%5C%2Cdx+%2B+4%5Cint%7Bx%5E%7B-1%2F2%7D%7D%5C%2Cdx%7D)
![\bold{2/7x^{7/2} - 2x^{3/2} + 8x^{1/2} + C} \bold{2/7x^{7/2} - 2x^{3/2} + 8x^{1/2} + C}](https://tex.z-dn.net/?f=%5Cbold%7B2%2F7x%5E%7B7%2F2%7D+-+2x%5E%7B3%2F2%7D+%2B+8x%5E%7B1%2F2%7D+%2B+C%7D)
I HOPE ITS HELP YOU DEAR,
THANKS
given function is
I HOPE ITS HELP YOU DEAR,
THANKS
Answered by
6
Hope it will help you!!
Attachments:
![](https://hi-static.z-dn.net/files/da1/edaa597514a2d1c7350f9a05a0c6921c.jpg)
Similar questions