Question

integration of cos^2x/cos^x sin^2x dx​

Answer 1

Answer:

[cos2x = cos²x - sin²x , use this here ] ⇒∫( cos²x - sin²x ).dx/sin²x.cos²x ⇒∫dx/sin²x - ∫dx/cos²x ⇒∫ cosec²x.dx - ∫sec²x.dx ⇒ -cotx - tanx ⇒-(sinx/cosx + cosx/ sinx ...