Question

integration of cos cube x sin cube x

Answer 1

${cos}^{3} x {sin}^{3} x \: dx \\ = {cos}^{3} x {sin}^{2} x \: sinx \\ let \: cosx = t \\ - sinxdx = dt \\ = - {t}^{3} (1 - {t}^{2} )dt \\ now \: integrate$