integration of cos2x-cos2y divided by sinx-siny=
Answers
Answered by
0
Answer:
as cos2x=1-2sin square x
- that is 1-2sin square x -(1-2sin square y)/sinx-siny)
- as a square-b square=(a-b)(a+b)
- that is 2(siny-sinx)(siny+sinx) /sinx-siny)
- -2sinx-2siny
- integration of sinx= - cosx
- then answer is 2cosx+2cosy+some constant
Similar questions