Question

Integration of dx/3x²+2x+1​

Answer 1

Answer:

${x}^{3} + {x}^{2} + x$

Step-by-step explanation:

dx/(3x^2 + 2x + 1)

= dx/3x^2 + dx/2x + dx/1

= 3(x^3)/3 + 2(x^2)/2 + (x^1)/1

= x^3 + x^2 + x

$\frac{dx}{3 {x}^{2} } + \frac{dx}{2x} + \frac{dx}{1} \\ \\ \frac{3 {x}^{2 + 1}}{2 + 1} + \frac{2 {x}^{1 + 1} }{1 + 1} + \frac{1 {x}^{0 + 1} }{0 + 1} \\ \\ \frac{3 {x}^{3} }{3} + \frac{2 {x}^{2} }{2} + \frac{1 {x}^{1} }{1} \\ \\ {x}^{3} + {x}^{2} + x$