integration of greatest integer of logx
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split from 1 to e and e to e^2
from 1 to e [lnx] has value= 0 in range 0 to 1
as ln 1= 0
and ln e = 1
from e to e^2, [ln x] has value 1 as lne = 1
and ln e^2 = 2
As we know upper limit is not included
so less than 2 , So greatest integer becomes 1
S0 0 + e^2 - 1
e^2 -1
(2) is correct
from 1 to e [lnx] has value= 0 in range 0 to 1
as ln 1= 0
and ln e = 1
from e to e^2, [ln x] has value 1 as lne = 1
and ln e^2 = 2
As we know upper limit is not included
so less than 2 , So greatest integer becomes 1
S0 0 + e^2 - 1
e^2 -1
(2) is correct
gaurav687:
bro ans 1st hai..
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