integration of sec^2/3x.cosec^4/3x dx
brunoconti:
u mean sec^2(3x) and not /3x
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integral sec^(2/3)(x) csc^(4/3)(x) x dx = (9 cos^2(x)^(1/3) sec(x) 2F1(1/3, 1/3, 4/3, sin^2(x)) - 6 x csc(x))/(2 csc^(2/3)(x) sec(x)^(1/3)) + constant
where F is a hypergeometric function
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