Question

integration of sec 3x​

Answer 1

Answer:

I don't understand your question....

Answer 2

Step-by-step explanation:

This can be done by spiltting ∫sec3(x)dx=∫sec2(x)sec(x)dx

Now solve this using integration by parts we get,

∫sec3xdx=sec(x)tan(x)−∫ tan(x)sec(x)tan(x)dx

Since 1+tan2(x)=sec2(x), we have tan2(x)=sec2(x)−1

∫ sec3(x)dx=∫ [sec3(x)−sec(x)]dx

→sec(x)tan(x)+ln|sec(x)+tan(x)|+C−∫ sec3(x)dx

your answer is this