integration of sec 3x
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Answer:
I don't understand your question....
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Step-by-step explanation:
This can be done by spiltting ∫sec3(x)dx=∫sec2(x)sec(x)dx
Now solve this using integration by parts we get,
∫sec3xdx=sec(x)tan(x)−∫ tan(x)sec(x)tan(x)dx
Since 1+tan2(x)=sec2(x), we have tan2(x)=sec2(x)−1
∫ sec3(x)dx=∫ [sec3(x)−sec(x)]dx
→sec(x)tan(x)+ln|sec(x)+tan(x)|+C−∫ sec3(x)dx
your answer is this
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