Math, asked by andriya40, 10 months ago

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Answered by SindhuSundar
1

Answer:

120 cm^2

Step-by-step explanation:

In the given figure, we have

PQ = QR

QS = QS (Common side)

Angle QSR = Angle QSP = 90

Thus, PQS is congruent to RQS

Their areas will be the same because they are congruent

ar(PQS) = ar(RQS) =1/2 * 15 * 8

ar(PQR) = ar(PQS) + ar(RQS)

             = 2*ar(RQS)

             = 2*1/2*15*8

             = 120 cm^2 (Option B)

Answered by seerat3219
1

Answer:

120cm²

Step-by-step explanation:

first we will find area of triangle QSR

it is right angle triangle so the formula is 1/2 ×base × height

1/2 ×15×8

60 cm²

now we will find the area of triangle PQS

it is right angle triangle so the formula is 1/2×base ×height

1/2×15×8

60cm²

now we will add area of both of the triangles

60cm²+60cm²

120cm2

hope this helps you

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