integration of sin^-1(cosx), I want in detail
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cosx=sin(x+π/2)
sin^-1 [sin(x+π/2)]= X +.π/2
it's integration= (x^2/2)+πx/2 +©
sin^-1 [sin(x+π/2)]= X +.π/2
it's integration= (x^2/2)+πx/2 +©
komaljangra:
thanks so much
welcome
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