Math, asked by komaljangra, 1 year ago

integration of sin^-1(cosx), I want in detail

Answers

Answered by saurabhsemalti

1

cosx=sin(x+π/2)
sin^-1 [sin(x+π/2)]= X +.π/2
it's integration= (x^2/2)+πx/2 +©

komaljangra: thanks so much

saurabhsemalti: welcome

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