Question

integration of sin 3x

Answer 1

ⓗⓔⓨⓐ ⓢⓐⓚⓢⓗⓘ ⓗⓔⓡⓔ

ⓗⓔⓡⓔ ⓘⓢ ⓤⓡ ⓐⓝⓢ

Answer 2

Hie!!

integration of Sin 3x dx

put 3x = z

Differentiate both sides w.r.t x we have

3 = dz/dx

dx = dz/3

integration of Sin z dz/3

- (Cos z) /3

- ( Cos 3x )/3 + k

Where k is called constant of integration.