Physics, asked by ghoullllll6969, 11 months ago

integration of
sin3x
Cos ^2xdx​

Answers

Answered by ss8534450
1

Answer:

/= ÷

1. sin3x

let t= 3x

dx/dt= 3

dx= dt/3

putting the value dx

integration sign sintdt/3

-cos3x/3

2. cos ^2xdx

2cos^2x sin^2 x/2

cos^2x sin^2

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