Math, asked by amanchugh2002, 9 months ago

integration of sinx+2cosx/cosx+sinx

Answers

Answered by Anonymous

4

Answer:

Step-by-step explanation

I

cosx-sinx)²= (2sinx)²

=>cos²x + sin²x-2sinxcosx=2sin²x

=> sin²x-2sin²x-2sinxcosx= -cos²x

=> -sin²x-2sinxcosx = -cos²x

=> sin²x+2sinxcosx=cos²x

=> sin²x +cos²x + 2sinxcosx=cos²x+cos²x [adding cos²x on both sides]

=> (sinx + cosx)² = 2cos²x

=> sinx + cosx = 2cosx

i hope it was helpful :p

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