Question

integration of sinx dx a( upper limit π/3 and the lower limit π/6)
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Answer 1

Answer:

ans is √3-1/2

plz mark brainliest

Answer 2

I hope I helped you dear have a good day

Explanation:

sin2x=1−(sinx−cosx)2

∫(sinx+cosx)dx1−(sinx−cosx)2−−−−−−−−−−−−−−−√

Let,

sinx−cosx=t

dtdx=sinx+cosx

∫dt1−t2−−−−−√

=arcsint=arcsin(sinx−cosx)

Putting limits,

=arcsin3–√−12−arcsin1−3–√2

As a sidenote, I have always been taught to substitute

sin2x=1+(sinx+cosx)2

when there are (sinx−cosx) and sin2x in the same integral.

sin2x=(sinx−cosx)2−1

when there are (sinx+cosx) and sin2x in the same integral. Although exceptions may exist.