integration of x^2+2x
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use the rule of x^n = x^(n+1)/n+1 and same for 2x the answer would be..
x^3/3+2x^2/2+c
x^3/3+2x^2/2+c
bharat7193:
same as that just use x^ n as 2x^2/2
Answered by
1
∫ ( x² + 2x ) dx
Applying Linearity, we get,
=> ∫ x² dx + 2 ∫ x dx => Equation 1
Now solving for ∫ x² dx
Applying Power rule,
xⁿ = xⁿ ⁺ ¹ / n + 1
=> In our case, n = 2
=> x² = x² ⁺ ¹ / 2 + 1
=> x² = x³ / 3
=> ∫ x² dx = x³ / 3
Now solving for 2 ∫ x dx
Applying Formula rule with n = 1 , we get,
=> x¹ + 1 / 1 + 1
=> x² / 2
=> 2 ∫ x dx = 2 * x² / 2 => x²
Substituting in Equation 1 we get,
=> x³ / 3 + x²
=> ∫ ( x² + 2x ) = x³ / 3 + x² + C.
Hence solved !
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