Question

integration of (π-x)^2​

Answer 1

check the attachment

Answer 2

∫(π−x)2 dx=−∫(π−x)2 (−dx)

=−∫(π−x)2 d(π−x)

=−(π−x)33+C

Alternatively,

∫(π−x)2 dx=∫(π2+x2−2πx) dx

=π2x+x33−2πx22+C

=π2x+x33−πx2+C