Math, asked by ufjvkh8320, 11 months ago

Integration of x^3-1/x^2 dx

Answers

Answered by srilathachahna
0

Answer:

x^4/4 + 1/2x

or 1/2(\frac{x^4}{2} + x )

Step-by-step explanation:

∫x³ - 1/ x² dx = ∫x³ dx - ∫1/x² dx

                    = \frac{x^4}{4} - (\frac{-1}{2x}) + c

                   = x^4/4  +  1/2x  + c

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