integration of x-sinx/1-cosx
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U=x-sin x
U'=1-cos x
V= 1-cos x
V'= sin x
Formula = vu'+uv'
=(1-cos x)(1-cos x) +(x-sin x)(sin x)
On solving we get.
X sin^2x-sin^3x
Hope it helps
U'=1-cos x
V= 1-cos x
V'= sin x
Formula = vu'+uv'
=(1-cos x)(1-cos x) +(x-sin x)(sin x)
On solving we get.
X sin^2x-sin^3x
Hope it helps
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