Math, asked by gurusharan29, 9 months ago

integration of x+sinxdx​

Answers

Answered by vithesh3399
0

Answer:

We want to integrate by parts, taking u = x, dv = sinx, du = dx, v = −cosx: ∫ x(sinx)dx = −xcosx + ∫ cosxdx = −xcosx + sinx + C . ∫ exxdx = xex − ∫ exdx = xex − ex + C .

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Answered by biligiri
0

Answer:

∫x + sin x dx

=> ∫ x dx + ∫ sin x dx

=> x²/2 + (-cos x ) + C

=> x²/2 - cos x + C

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