Question

integration of x square + 3 X + 4 x + 5 x square + 6 x minus 1 by 10

Answer 1

$integration \: of \: {x}^{2} + 3x + 4x + 5 {x}^{2} + 6x - \frac{1}{10 } \\ = integration \: of 6{x }^{2} + 13x - \frac{1}{10 } \\ = 6 \times \frac{ {x}^{3} }{3} + 13 \frac{ {x}^{2} }{2} - \frac{1}{10} x + c \\ = 2 {x}^{3} + \frac{13 {x}^{2} }{2} - \frac{x}{10} + c$