Question

Integration of [x / (x^2 +1)^2 ] dx

Answer 1

Let x^2+1 = t

2x*dx=dt

x*dx

dt\2

so for this { x\{x^2+1}^2}*dx

1\2*∫ dt\t^2

1\2{t^-2+1\-2+1}

1\2*t^-1