Math, asked by arnavpol68, 11 months ago

integration of x²/(4+x²) dx​

Answers

Answered by PhysicsForever
2

Answer:

Integral x^2 / x^2 + 4

= Integral x^2+4-4/x^2+4

= Integral of x^2+4/x^2+4 - 4(1/x^2+4)

= Integral of 1- 4(1/x^2 + (2)^2)

= x - 4/2 tan^-1(x/2) + c

= x - 2 tan^-1 (x/2) + c

I'm assuming here that the integration is done obviously with respect to x since nothing has been. specified otherwise.

Hope this helps you !

Pre - requisites used

Integral of x^n = x^n+1/n+1 + c

Provided n is not equal to -1

for n = -1

that is

Integral of x^-1 = ln|x| + c

and, also

Integral of 1/x^2 + (a)^2 = 1/a tan^-1 (x/a) + c

Answered by anamkhurshid29
1

HEYA MATE YOUR ANSWER IS

x^2/4+x^2

= 2x^3/2x^3

= 1

Hope this helps ❤️

Please mark as brainliest ❤️

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