integration.......pls anyone here
Attachments:
innervoice:
better ...use by parts method
taking e^x as 1st function nd 1/x^2 as 2nd function
ok..... thanks ☺☺
wlcm..
yes
Answers
Answered by
1
integration £ e^x ( 1/x^2)dx
if we supposed integration sign = £
I = 1/x^2 (£ e^x dx ) - £ (-2/x) (£ e^x dx) dx
I =( 1/x^2 ). (e^x) + 2 £ (e^x / x) . dx
I = e^x / x^2 + (e^x).(ln x) - £ e^x.(lnx) . dx
I = e^x / x^2 + (e^x).(lnx) - e^x lnx + e^x / x + £ (e^x) (1/x^2 ) dx
if we supposed integration sign = £
I = 1/x^2 (£ e^x dx ) - £ (-2/x) (£ e^x dx) dx
I =( 1/x^2 ). (e^x) + 2 £ (e^x / x) . dx
I = e^x / x^2 + (e^x).(ln x) - £ e^x.(lnx) . dx
I = e^x / x^2 + (e^x).(lnx) - e^x lnx + e^x / x + £ (e^x) (1/x^2 ) dx
shayad mene hi koi galati ki ho
to please maf kr dena ..!!!!
nhi wo bat nhi h
Please ya to pura btao but ye wo bat mt bolo please.....
jo bolna h clearly btao
kuch nhi bolna
okkk as ur wish yr .....
please maaf kr dena koi galati ki ho to
meko nhi lgta ab aap meri dost h ..... right
kk byyye.....yr......
Similar questions