integration(√tanx + √cotx) dx is equals to
Answers
Answered by
0
Answer:
∫
tanx
+
cotx
dx=∫
cosx
sinx
+
sinx
cosx
dx
∫
sinxcosx
sinx+cosx
dx=
2
∫
2sinxcosx
sinx+cosx
dx
=
2
∫
2sinxcosx+1−1
sinx+cosx
dx=
2
∫
1−(sinx−cosx)
2
sinx+cosx
dx
put sinx−cosx=t (sinx+cosx)=dt
=
2
∫
1−t
2
dt
=
2
sin
−1
t+c
=
2
sin
−1
(sinx−cosx)+c
Answered by
0
Step-by-step explanation:
bro brain list mark kar de bahut mehnat se likha hai
Attachments:
Similar questions